P paulchondo May 2010 1 0 May 13, 2010 #1 I have a question that says, Evaluate the following limit- limit as h-->1 (x^3000 - 1) / (x-1) Thank-you. -Paul

I have a question that says, Evaluate the following limit- limit as h-->1 (x^3000 - 1) / (x-1) Thank-you. -Paul

Prove It MHF Helper Aug 2008 12,883 4,999 May 13, 2010 #2 paulchondo said: I have a question that says, Evaluate the following limit- limit as h-->1 (x^3000 - 1) / (x-1) Thank-you. -Paul Click to expand... Since it does not depend on \(\displaystyle h\), the limit is \(\displaystyle \frac{x^{3000} - 1}{x - 1}\).

paulchondo said: I have a question that says, Evaluate the following limit- limit as h-->1 (x^3000 - 1) / (x-1) Thank-you. -Paul Click to expand... Since it does not depend on \(\displaystyle h\), the limit is \(\displaystyle \frac{x^{3000} - 1}{x - 1}\).

Random Variable May 2009 959 362 May 13, 2010 #3 I'll assume you meant \(\displaystyle \lim_{x \to 1} \ \frac{x^{3000}-1}{x-1} \) \(\displaystyle = \lim_{x \to 1} \frac{(x-1)(x^{2999} +x^{2998}+....+x+1)}{x-1} = 3000\)

I'll assume you meant \(\displaystyle \lim_{x \to 1} \ \frac{x^{3000}-1}{x-1} \) \(\displaystyle = \lim_{x \to 1} \frac{(x-1)(x^{2999} +x^{2998}+....+x+1)}{x-1} = 3000\)