Q: Find the Maclaurin polynomial of order 3 for the function f(x) = e^(-2x).
I know that the Maclaurin polynomial for e^x = 1 + x + x^2/2! + x^3/3! + ...
So my question is if I would have to plug in (-2x) in the Maclaurin polynomial of e^x so I get
e^(-2x) = 1 - 2x + 2x^2 - 4x^3/3 + ...
Is this right or wrong?
I know that the Maclaurin polynomial for e^x = 1 + x + x^2/2! + x^3/3! + ...
So my question is if I would have to plug in (-2x) in the Maclaurin polynomial of e^x so I get
e^(-2x) = 1 - 2x + 2x^2 - 4x^3/3 + ...
Is this right or wrong?