-Dan

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-Dan

defines the term points. gaps as a concept was introduced,differs from the "standard" Euclidean geometry approach?

-Dan

Since you have the most current knowledge in mathematics ask you a question , we have \(\displaystyle a=\{0,4\}\cup\{6,9\}\cup\{11,13\}\) , \(\displaystyle b=\{0,3\}\cup\{5,10\}\) that should be applied a mathematical method to obtain different results of\(\displaystyle c_n\)

\(\displaystyle c_1=(1,1,1,2)\) My notation and solution \(\displaystyle 4\underline23\underline22{+_1^{\underline0}}3 \underline25=(1,1,1,2)\) ...

\(\displaystyle c_2=(1,4)\) --\(\displaystyle 4\underline23\underline22{+_1^{\underline1}}3 \underline25=(1,4)\)...

\(\displaystyle c_3=(2,1,1,2,1)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline2}}3 \underline25=(2,1,1,2,1)\)...

\(\displaystyle c_4=(3,4,2)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline3}}3 \underline25=(3,4,2)\)...

\(\displaystyle c_5=(6,4,1)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline4}}3 \underline25=(6,4,1)\)...

\(\displaystyle c_6=(4,1,1,1,2)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline5}}3 \underline25=(4,1,1,1,2)\)...

\(\displaystyle c_7=(4,3)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline6}}3 \underline25=(4,3)\)...

\(\displaystyle c_8=(4,1,1,1,4)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline7}}3 \underline25=(4,1,1,1,4)\)...

\(\displaystyle c_9=(4,2,9)\)---\(\displaystyle 4\underline23\underline22{+_1^{\underline8}}3 \underline25=(4,2,9)\)...

\(\displaystyle c_{10}=(4,5,5)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline9}}3 \underline25=(4,5,5)\)...

\(\displaystyle c_{11}=(4,3,1,5)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline{10}}}3 \underline25=(4,3,1,5)\)...

\(\displaystyle c_{12}=(4,3,1,5)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline{11}}}3 \underline25=(4,3,1,5)\)...

\(\displaystyle c_{13}=(4,3,2,5)\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline{12}}}3 \underline25=(4,3,2,5)\)...

\(\displaystyle c_{14}=(4,3,3,5\)--\(\displaystyle 4\underline23\underline22{+_1^{\underline{13}}}3 \underline25=(4,3,3,5)\)

show me the solution for the first part

I'll take for granted that you have done this correctly in terms of your notation. But what does it actually mean? What advantage do we get by putting it in terms of this notation?defines the term points. gaps as a concept was introduced,

Since you have the most current knowledge in mathematics ask you a question , we have \(\displaystyle a=\{0,4\}\cup\{6,9\}\cup\{11,13\}\) , \(\displaystyle b=\{0,3\}\cup\{5,10\}\) that should be applied a mathematical method to obtain different results of\(\displaystyle c_n\)

\(\displaystyle c_1=(1,1,1,2)\) My notation and solution \(\displaystyle 4\underline23\underline22{+_1^{\underline0}}3 \underline25=(1,1,1,2)\) ...

-Dan

whether current mathematics has solutions for different values of \(\displaystyle c_n\) for the values of \(\displaystyle a\) and \(\displaystyle b\), if no then my math betterI'll take for granted that you have done this correctly in terms of your notation. But what does it actually mean? What advantage do we get by putting it in terms of this notation?

-Dan

-Dan

Unfortunately, some people then get the idea that, if they write gibberish, they are writing mathematics!

If you ask a task and you have no solution to the task, then something is wrong with the current math, and I offer you the method of possible solutions, you say that it's a fool. So please if you are nice to your knowledge of mathematics offers a process by which a decision ...

Unfortunately, some people then get the idea that, if they write gibberish, they are writing mathematics!

-Dan

\(\displaystyle -2\underline{-1} -2\underline 1 2\)

-Dan

intended HallsofIvy , your knowledge of current mathematics (http://mathhelpforum.com/peer-math-review/239253-function-point-2.html March 25th 2015, 06:26 AM )

that geometric object in the plane meets these requirements

a ) has six angles

b )the sum of the angles \(\displaystyle 1080^o\)

- has six angles \(\displaystyle \angle ABC\) , \(\displaystyle \angle BCA\) , \(\displaystyle \angle CAB\) , \(\displaystyle \angle DEF\) , \(\displaystyle \angle EFD\) , \(\displaystyle \angle FED\)

- the sum of the angles \(\displaystyle 1080^o\)

program for computer Mathematica

Code:

```
Options[plus1] = {"Output" -> "Standard"};
plus1[a_, b_, c_, OptionsPattern[]] :=
If[OptionValue["Output"] == "Standard", Identity, toEncoded]@
BitXor[a, c 2^b]
fromEncoded[a_] :=
FromDigits[
Reverse[Flatten[
ConstantArray @@@
Transpose[{PadRight[{}, Length[a], {1, 0}], a}]]], 2]
toEncoded[n_] :=
Length /@ Select[Split[[email protected][n, 2]], First[#] == 1 &]
toEncoded[5] (*outputs {1,1}*)
fromEncoded[{1,1}] (*outputs 5*)
plus1[fromEncoded[{4, 2, 3, 2, 2}], [COLOR="#FF0000"]5[/COLOR], fromEncoded[{3, 2, 5}],
"Output" -> "Nonstandard"]
```

Proof - \(\displaystyle 1\rightarrow 1 (\underline{s})\)

\(\displaystyle 4{+_3^{\underline0}}2=2\)

\(\displaystyle 4{+_3^{\underline1}}2=2\)

\(\displaystyle 4{+_3^{\underline2}}2=2\)

\(\displaystyle 4{+_3^{\underline3}}2=4\)

\(\displaystyle 4{+_3^{\underline4}}2=6\)

\(\displaystyle +_3 \)- addition rule 3

(SM.) - no "addition rule 3 "

NOTE, the previous \(\displaystyle +_3\) becomes \(\displaystyle +_4\) , the previous\(\displaystyle +_4\) becomes \(\displaystyle +_5\)

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