# logarithm

#### sandy

i really need help in this , i have no idea at all , help!

Use logarithms to find all solutions of the following equations
(a)
e^z = e

(b) e^z = e^(-z)

#### chisigma

MHF Hall of Honor
a) $$\displaystyle e^{z} = e \rightarrow z= 1 + 2 k \pi i$$

b) $$\displaystyle e^{z} = e^{-z} \rightarrow z = k \pi i$$

... where in both cases k is an integer...

Kind regards

$$\displaystyle \chi$$ $$\displaystyle \sigma$$

sandy