A aPexDrifta Apr 2010 3 0 May 13, 2010 #1 I'm not really sure where to begin with this one. Any help would be greatly appreciated.

skeeter MHF Helper Jun 2008 16,216 6,764 North Texas May 13, 2010 #2 aPexDrifta said: I'm not really sure where to begin with this one. Any help would be greatly appreciated. Click to expand... \(\displaystyle \bar{y} = \frac{y}{2}\) \(\displaystyle dA = y \, dx\) \(\displaystyle y_c = \frac{\frac{1}{2} \int_0^b y^2 \, dx}{\int_0^b y \, dx}\) where \(\displaystyle y = H\sin\left(\frac{\pi x}{b}\right) \)

aPexDrifta said: I'm not really sure where to begin with this one. Any help would be greatly appreciated. Click to expand... \(\displaystyle \bar{y} = \frac{y}{2}\) \(\displaystyle dA = y \, dx\) \(\displaystyle y_c = \frac{\frac{1}{2} \int_0^b y^2 \, dx}{\int_0^b y \, dx}\) where \(\displaystyle y = H\sin\left(\frac{\pi x}{b}\right) \)

A aPexDrifta Apr 2010 3 0 May 13, 2010 #3 Thank you, that's exactly what I needed. It makes much more sense now