# Location of a Centroid

#### aPexDrifta

I'm not really sure where to begin with this one. Any help would be greatly appreciated.

#### skeeter

MHF Helper
I'm not really sure where to begin with this one. Any help would be greatly appreciated.

$$\displaystyle \bar{y} = \frac{y}{2}$$

$$\displaystyle dA = y \, dx$$

$$\displaystyle y_c = \frac{\frac{1}{2} \int_0^b y^2 \, dx}{\int_0^b y \, dx}$$

where $$\displaystyle y = H\sin\left(\frac{\pi x}{b}\right)$$

#### aPexDrifta

Thank you, that's exactly what I needed. It makes much more sense now