Prove that \(\displaystyle T\) nilpotent if and only if the characteristic polynomial of \(\displaystyle T\) is \(\displaystyle x^n\)

Thank you!

- Thread starter Also sprach Zarathustra
- Start date

Similar Math Discussions | Math Forum | Date |
---|---|---|

Radicals: is each locally nilpotent ring a nil? | Algebra | |

Locally convex set | Calculus | |

Locally Lipschitz function is bounded | Differential Geometry | |

SOLVED locally compact spaces | Differential Geometry |