Limits with taylor

Nov 2018
32
3
Italy
Where do i get wrong?
The limit is supposed to be equal to 0
I'm getting out of my mind ><


Sent from my Redmi Note 4X using Tapatalk
 
Jun 2013
1,112
590
Lebanon
\(\displaystyle \text{Log}\left(1+x+\frac{x^2}{2}\right)=x-\frac{x^3}{6}+\text{...}\)
 
  • Like
Reactions: 1 person
Nov 2018
32
3
Italy
\(\displaystyle \text{Log}\left(1+x+\frac{x^2}{2}\right)=x-\frac{x^3}{6}+\text{...}\)
How do i read what u wrote in the answer? Btw thx for answering... I read like {Log}\left(1+x etc..)
I mean how do i translate it? ^^

Sent from my Redmi Note 4X using Tapatalk
 
Dec 2011
2,314
916
St. Augustine, FL.
How do i read what u wrote in the answer? Btw thx for answering... I read like {Log}\left(1+x etc..)
I mean how do i translate it? ^^
Do you have javascript disabled? If so, you will need to enable it.
 

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
Are you saying you do not understand what "log" means?