pickslides MHF Helper Sep 2008 5,237 1,625 Melbourne Mar 8, 2010 #2 which is your problem? \(\displaystyle \frac{4}{x}+5 > \frac{1}{2x}+3 \) or \(\displaystyle \frac{4}{x}+5 > \frac{1}{2}x+3 \)

which is your problem? \(\displaystyle \frac{4}{x}+5 > \frac{1}{2x}+3 \) or \(\displaystyle \frac{4}{x}+5 > \frac{1}{2}x+3 \)

M Mhockey02 Mar 2010 14 0 Mar 8, 2010 #3 4 > 1 x+5 2x+3 also, how did you post a fraction like that? thanks!

pickslides MHF Helper Sep 2008 5,237 1,625 Melbourne Mar 8, 2010 #4 This one? \(\displaystyle \frac{4}{x+5} > \frac{1}{2x+3}\) Mhockey02 said: also, how did you post a fraction like that? thanks! Click to expand... Click on the text, it will tell you.

This one? \(\displaystyle \frac{4}{x+5} > \frac{1}{2x+3}\) Mhockey02 said: also, how did you post a fraction like that? thanks! Click to expand... Click on the text, it will tell you.

pickslides MHF Helper Sep 2008 5,237 1,625 Melbourne Mar 8, 2010 #6 \(\displaystyle \frac{4}{x+5} > \frac{1}{2x+3}\) Well first off you cross multiply giving... \(\displaystyle 4(2x+3) >x+5\) Then expanding the LHS you get... \(\displaystyle 8x+12 >x+5\) Can you finish it from here? Reactions: Mhockey02

\(\displaystyle \frac{4}{x+5} > \frac{1}{2x+3}\) Well first off you cross multiply giving... \(\displaystyle 4(2x+3) >x+5\) Then expanding the LHS you get... \(\displaystyle 8x+12 >x+5\) Can you finish it from here?