is this possible? angles and stuff

Sep 2018
2
0
MD
IMG_0757.jpg
So one of my friends sent me this thing today and I was able to figure out all the questions but 4 and 5. I know she's wrong for the other questions (all 3 I believe) but neither of us could figure out what the correct answers to 4 and 5 were. I don't think it's possible but I figure I'd let a bunch of other people much better at math than me try.
 

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
Problem 5 says "find x" but where is x? There is no "x" in the stated conditions or in the picture given.

Also you say you are concerned about problem "4 and 5" but what you show are problems 5 and 6.
 
Sep 2018
2
0
MD
My bad I meant problem D and E from question 5. This is all the information for this problem; x is just a random number used in the equation to find the angles - it's not a specific angle or line or point or anything.
 

Plato

MHF Helper
Aug 2006
22,490
8,653
My bad I meant problem D and E from question 5. This is all the information for this problem; x is just a random number used in the equation to find the angles - it's not a specific angle or line or point or anything.

\(\displaystyle \begin{array}{l} 8x + 2 &= 90\\ 6x &= 88\\ x &= 11 \end{array}\) so $\begin{array}{l} M(\angle 2)&=6(11)+2\\&=68 \end{array}$
 
Dec 2016
302
165
Earth
\(\displaystyle \begin{array}{l} 8x + 2 &= 90\\ 6x &= 88\\ x &= 11 \end{array}\) so $\begin{array}{l} M(\angle 2)&=6(11)+2\\&=68 \end{array}$
There was a typo in the second line above.


\(\displaystyle \begin{array}{l} 8x + 2 &= 90\\ 8x &= 88\\ x &= 11 \end{array}\) so $\begin{array}{l} M(\angle 2)&=6(11)+2\\&=68 \end{array}$
 
Feb 2015
2,255
510
Ottawa Ontario
Plato's 1st typo this year?