Inverse Trigonometric Function

romsek

MHF Helper
Nov 2013
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California
?

let's use $\theta$ for angles and $x$ for lengths

$\tan(\theta) = \dfrac{1}{\cot(\theta)} = x$

$\tan^{-1}(x) = \theta = \cot^{-1}\left(\dfrac 1 x\right)$
 
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