intergrate

mr fantastic

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Dec 2007
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intergral of 3x/3x-2 dx
Note that \(\displaystyle \displaystyle \frac{3x}{3x - 2} = \frac{(3x - 2) + 2}{3x - 2} = 1 + \frac{2}{3x - 2}\).
 
Oct 2010
252
76
Gampaha, Sri Lanka
\(\displaystyle \frac{3x}{3x-2}=1+\frac{2}{3x-2}\)

now it's easy to integrate
 
Oct 2008
46
0
So, after that do i do u= 3x-2
du= 3 dx? or what is the next step?
 
Oct 2008
46
0
my answer comes to x+(2/3)ln[3x-2]+c, is that correct?
 
Oct 2010
252
76
Gampaha, Sri Lanka
\(\displaystyle x+\frac{2}{3}ln|3x-2|+c\)

NOTE: differentiate and you can check your answer for yourself
 
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