intergrate

[homerb]

intergral of 3x/3x-2 dx

 

[mr fantastic]

intergral of 3x/3x-2 dx

Note that \(\displaystyle \displaystyle \frac{3x}{3x - 2} = \frac{(3x - 2) + 2}{3x - 2} = 1 + \frac{2}{3x - 2}\).

 

[BAdhi]

\(\displaystyle \frac{3x}{3x-2}=1+\frac{2}{3x-2}\)

now it's easy to integrate

 

[homerb]

So, after that do i do u= 3x-2
du= 3 dx? or what is the next step?

 

[mr fantastic]

So, after that do i do u= 3x-2
du= 3 dx? [snip]

Yes.

 

[homerb]

my answer comes to x+(2/3)ln[3x-2]+c, is that correct?

 

[BAdhi]

\(\displaystyle x+\frac{2}{3}ln|3x-2|+c\)

NOTE: differentiate and you can check your answer for yourself