# Intercepts

#### OneidaFL

(1) 4x-12 = 34

Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.

(2) -25X + Y = 55

What is the Y intercept

What is the X intercept

#### pickslides

MHF Helper
(1) 4x-12 = 34

Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.
$$\displaystyle 4x-12 = 34$$

$$\displaystyle 4x = 46$$

$$\displaystyle x = \frac{46}{4}$$

(2) -25X + Y = 55

What is the Y intercept

What is the X intercept
y-intercept make x = 0

$$\displaystyle -25X + Y = 55$$

$$\displaystyle -25\times 0 + Y = 55$$

Now solve for y

x-intercept make y = 0

$$\displaystyle -25X + Y = 55$$

$$\displaystyle -25X + 0 = 55$$

Now solve for x

#### Prove It

MHF Helper
(1) 4x-12 = 34

Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.

(2) -25X + Y = 55

What is the Y intercept

What is the X intercept
1. This is not the equation of a line.

2. To find the $$\displaystyle x$$ intercept, let $$\displaystyle y = 0$$ and solve for $$\displaystyle x$$.

To find the $$\displaystyle y$$ intercept, let $$\displaystyle x = 0$$ and solve for $$\displaystyle y$$.

downthesun01

#### pickslides

MHF Helper
1. This is not the equation of a line.
Or maybe the equation of a vertical line?

downthesun01

#### downthesun01

(1) Solving for x will give you your x-intercept. Since there is no y, it's obvious that this is a vertical (|) line running parallel to the x-axis.

(2)To find the x-intercept set y=0 and solve for x.

So,

$$\displaystyle -25x+(0)=55$$ Solve for x

To find the y-intercepts set x=0 and solve for y.

So,

$$\displaystyle -25(0)+y=55$$ Solve for y.

Hope that helps

#### Prove It

MHF Helper
Or maybe the equation of a vertical line?
True, but that's not what the question sounds like...

From the sound of the question, there should be an equation of the form $$\displaystyle y = mx + c$$, so that you can graph it either using the intercepts, or the $$\displaystyle y$$-intercept and gradient.

#### downthesun01

1. This is not the equation of a line.

Pickslides is right. It's the equation of a vertical line. You can think of y being equal to 0.

#### pickslides

MHF Helper
True, but that's not what the question sounds like...

From the sound of the question, there should be an equation of the form $$\displaystyle y = mx + c$$, so that you can graph it either using the intercepts, or the $$\displaystyle y$$-intercept and gradient.
Agreed. It does seem like a strange one to be asked.