pickslides MHF Helper Sep 2008 5,237 1,625 Melbourne May 26, 2010 #2 Do you mean \(\displaystyle y=\frac{x^2-4}{x^2-9}\) ??

pickslides MHF Helper Sep 2008 5,237 1,625 Melbourne May 26, 2010 #4 \(\displaystyle y=\frac{x^2-4}{x^2-9}=\frac{x^2-4}{(x-3)(x+3)}\) What are the vertical asymptotes?

pickslides MHF Helper Sep 2008 5,237 1,625 Melbourne May 26, 2010 #6 eichyess said: i dont know? Click to expand... Last hint: \(\displaystyle (x-3)(x+3)\neq 0\)