Could you please help me with Integration : [sec sqrt(x)]^2 / 2 sqrt (x) ( 1+[tan sqrt(x)]^2]

First i simplified it :

sec sqrt(x)]^2 is equivalent to 1+[tan sqrt(x)]^2] I cancel them out.

1/2 sqrt(x) would remain.

Then the integration is equal to :

1/2 Integral x^ -1/2

The final answer is :

( x^1/2)

Please let me know if my answer is correct.

I would really appreciate it if you show me the correct solution.