integrating factor

Mar 2014
909
2
malaysia
is my integral R(x) and R(y) correct ? why it look so complicated ? 0060.jpg
 
Dec 2013
2,000
757
Colombia
Neither are integrating factors because they are not expressions in a single variable. Can you post the full text of the question?
 
Mar 2014
909
2
malaysia
Neither are integrating factors because they are not expressions in a single variable. Can you post the full text of the question?
the full text is Show that the first order differential equation is EXACT equation . (sin x - x sin y) dx + (cos y + y cos x ) dy = 0
 
Dec 2013
2,000
757
Colombia
Perhaps the differentials are transposed. The following is exact:
$$(\sin x - x\sin y) \,\mathrm d y + (\cos y + y \cos x)\,\mathrm d x = 0 \\ \implies y\sin x + x\cos y = c$$
 
Mar 2014
909
2
malaysia
Perhaps the differentials are transposed. The following is exact:
$$(\sin x - x\sin y) \,\mathrm d y + (\cos y + y \cos x)\,\mathrm d x = 0 \\ \implies y\sin x + x\cos y = c$$
you mean the dy and dx should be interchanged , so that the equation is EXACT ?
 
Dec 2013
2,000
757
Colombia
That's not a valid operation. I'm suggesting that the question has been written incorrectly.
 
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Mar 2014
909
2
malaysia
Perhaps the differentials are transposed. The following is exact:
$$(\sin x - x\sin y) \,\mathrm d y + (\cos y + y \cos x)\,\mathrm d x = 0 \\ \implies y\sin x + x\cos y = c$$
i tried this , but still didint get the answer . Is there any other alternative for this question?
 
Dec 2013
2,000
757
Colombia
What answer are you looking for?