# integrate (x^3)(cosh2x)

#### xl5899

why the ans from the tabular method is different from the by part method ? why the ans from for each term of tabular method is more than the by part method by 1/2 ?

#### xl5899

can someone help pls ? thanks in advance !

#### Wander

Hello.

What exactly is the problem? The end results don't seem different to me.

#### xl5899

Hello.

What exactly is the problem? The end results don't seem different to me.
the first terms of the ans from the tabular method is(x^3)(cosh 2 x) , but not 1/2(x^3)(sinh 2 x) ... and so on....
but the final ans below the tabular method there give 1/2(x^3)(sinh 2 x) , tat's weird

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#### Wander

Remember that we move diagonally with the tabular approach - not directly across.

First, we have the positive term given by the product of $$\displaystyle x^3$$ and $$\displaystyle \frac{1}{2}\sinh(2x)$$ .

Then, we have the negative term given by the product of $$\displaystyle -3x^2$$ and $$\displaystyle \frac{1}{4}\cosh(2x)$$ .

...And so forth.

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1 person

Ok