# Integrate 1/(xln²x) with respect to x by change of variable.

#### feyomi

I'm struggling to find a suitable substitution.
If I know one then I should be able to work it out from there.
Thanks for any help.

#### General

put $$\displaystyle u=ln(x) \implies du=\frac{dx}{x}$$

So the integral will be : $$\displaystyle \int \frac{du}{u^2}=\frac{-1}{u}+C=\frac{-1}{ln(x)} + C$$