SOLVED integral of secxtanx

Jul 2010
86
0
Integral of secxtanx dx [pi/3,pi/4]

soo

[sec(pi/3)-sec(pi/4)]
= 2-1
=1?
Correct?
 
Jul 2010
58
27
Brazil
\(\displaystyle \sec (\pi/3) = 2\)

\(\displaystyle \sec (\pi/4) = \sqrt{2}\)

So, \(\displaystyle \sec (\pi/3) - \sec (\pi/4) = 2-\sqrt{2}\)
 
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