alright so this is the question,

so first i set that 3x^2+3x+2=>0 and i get that x=>-1 x<=-2

for x^2-x+1 i notice it's always above zero

next i do to the power of 2 on both sides and after solving what i got, i get the next boundry

(-1-sqrt(13))/6<x<(-1+sqrt(13))/6 and here i think im dont but the right answer is

x<=-2 -1<=x<(-1+sqrt(13))/6

if any one could explain why it is what it is, would be much helpful