Indices Evaluation Question

Feb 2010
34
0
Sorry to trouble fellow forumers again with this indices question:

Without using a calculator, evaluate 6^x, given that 3^(x+1) multiply by 2^(2x+1) = 2^(x+2).

Thanks in advance!(Happy)
 
Jun 2009
806
275
Sorry to trouble fellow forumers again with this indices question:

Without using a calculator, evaluate 6^x, given that 3^(x+1) multiply by 2^(2x+1) = 2^(x+2).

Thanks in advance!(Happy)
\(\displaystyle 3^x*3*2^{2x}*2 = 2^x*2^2\)

\(\displaystyle 3^x*3*2^x*2 = 2^2\)

\(\displaystyle 6^x*6 = 4\)
Now find the answer.
 
Nov 2009
927
260
Wellington
\(\displaystyle 3^x*3*2^{2x}*2 = 2^x*2^2\)

\(\displaystyle 3^x*3*2^x*2 = 2^2\)

\(\displaystyle 6^x*6 = 4\)
Now find the answer.
Hi Sa-ri-ga-ma, you can use the command \times (\(\displaystyle \times\)) to output the nice multiplication symbol :)