Increasing absolute min

Mar 2010
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0
Prove: If I:=[a,b] is an interval and f:I->R, R,reals is an increasing function, then the point a [respectively,b] is an absolute minimum [respectively, maximum] point for f on I. If f is strictly increasing, then a is the only absolute minimum point for f on I.
 

Drexel28

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Prove: If I:=[a,b] is an interval and f:I->R, R,reals is an increasing function, then the point a [respectively,b] is an absolute minimum [respectively, maximum] point for f on I. If f is strictly increasing, then a is the only absolute minimum point for f on I.
This is merely unraveling the definitions. What do you think?