R realbrandon Oct 2014 133 2 Florida Apr 18, 2016 #1 How do I know what it is supposed to be? Please explain. Thank you!

skeeter MHF Helper Jun 2008 16,217 6,765 North Texas Apr 18, 2016 #2 Re: If (a,b) is a point on the terminal side of angle t in standard position, then co sketch a reference triangle ... adjacent side = a opposite side = b hypotenuse = ? cosine is the ratio = $\dfrac{\text{? side}}{\text{? side}}$ Reactions: 1 person

Re: If (a,b) is a point on the terminal side of angle t in standard position, then co sketch a reference triangle ... adjacent side = a opposite side = b hypotenuse = ? cosine is the ratio = $\dfrac{\text{? side}}{\text{? side}}$

R realbrandon Oct 2014 133 2 Florida Apr 22, 2016 #3 Re: If (a,b) is a point on the terminal side of angle t in standard position, then co Cosine is the ration of adjacent/hypotenuse. Does that then make the answer c. a/sqrt a^2 + b^2?

Re: If (a,b) is a point on the terminal side of angle t in standard position, then co Cosine is the ration of adjacent/hypotenuse. Does that then make the answer c. a/sqrt a^2 + b^2?

skeeter MHF Helper Jun 2008 16,217 6,765 North Texas Apr 22, 2016 #4 Re: If (a,b) is a point on the terminal side of angle t in standard position, then co realbrandon said: Cosine is the ratio of adjacent/hypotenuse. Does that then make the answer c. a/sqrt(a^2 + b^2)? Click to expand... fixed ...

Re: If (a,b) is a point on the terminal side of angle t in standard position, then co realbrandon said: Cosine is the ratio of adjacent/hypotenuse. Does that then make the answer c. a/sqrt(a^2 + b^2)? Click to expand... fixed ...