How to convert a hyperbolic system to cartesian?


Forum Staff
Jan 2006
Wellsville, NY
I want to convert this system of corrdinates (see image beloow) to cartesian system. How make this?
Given Cartesian coordinates x and y, we get hyperbolic coordinates u and v given by
\(\displaystyle u = ln \left ( \sqrt{ \frac{x}{y} } \right )\)

\(\displaystyle v = \sqrt{xy}\)

Take the exponential of the u equation:
\(\displaystyle e^u = \sqrt{\frac{x}{y}}\)

Now take \(\displaystyle v e^{u} = \sqrt{\frac{x}{y}} \cdot \sqrt{xy} = x\)

So then subbing the x value into the equation for v:
\(\displaystyle v = \sqrt{ v e^u \cdot y}\)

Solve for y and you get the Cartesian coordinates
\(\displaystyle x = v e^u\) and \(\displaystyle y = v e^{-u}\)

Apr 2015
Somerset, England
Actually you didn't post any system above, only a link.

I see no reason to go roaming the net in search of the biggest half of your question.

Post your question here.
Then it might be answered here.