M math951 Jul 2015 564 14 United States Nov 4, 2019 #1 Third Moment: \(\displaystyle E[z^3] = \dfrac{1}{\sqrt{2\pi}}\int_{- \infty}^{\infty} z^3 \bullet e^\dfrac{-z^2}{2} ~ dz\) Last edited: Nov 4, 2019

Third Moment: \(\displaystyle E[z^3] = \dfrac{1}{\sqrt{2\pi}}\int_{- \infty}^{\infty} z^3 \bullet e^\dfrac{-z^2}{2} ~ dz\)

romsek MHF Helper Nov 2013 6,647 2,994 California Nov 4, 2019 #2 odd function times even function is? odd function integrated over symmetric interval is?

M math951 Jul 2015 564 14 United States Nov 4, 2019 #3 What about the fourth moment? Is the best approach to do tabular method?

M math951 Jul 2015 564 14 United States Nov 4, 2019 #4 Assuming I have midterm that is 50 minutes long...so 10 minutes to do problem each.