How does one prove this identity?

May 2010
20
0
\(\displaystyle \nabla\cdot[v(x\cdotv)]=\nabla(\frac{1}{2}v^2x)-\frac{1}{2}v^2+v\cdot(x\timesw\)
 

dwsmith

MHF Hall of Honor
Mar 2010
3,093
582
Florida
\(\displaystyle \nabla\cdot[v(x\cdotv)]=\nabla(\frac{1}{2}v^2x)-\frac{1}{2}v^2+v\cdot(x\timesw\)
\(\displaystyle Latex error\to correct formatting\to help received\) (Bigsmile)
 
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