1.x+3/2x>1

2.4/x+1<3/1

3.3/x-2≤1

i know theres a method for this to find 2 solutions but i dont remember it can someone please help

What you have written is extremely confusing... Please use brackets where they're needed.

I.e. in Q1 is it \(\displaystyle \frac{x + 3}{2x} > 1\) or \(\displaystyle x + \frac{3}{x} > 1\)?

Is Q2 \(\displaystyle \frac{4}{x + 1} < \frac{3}{1}\) or \(\displaystyle \frac{4}{x} + 1 < \frac{3}{1}\)?

Is Q3 \(\displaystyle \frac{3}{x - 2} \leq 1\) or \(\displaystyle \frac{3}{x} - 2 \leq 1\)?