help with these inequalities

May 2010
39
0
1.x+3/2x>1
2.4/x+1<3/1
3.3/x-2≤1

i know theres a method for this to find 2 solutions but i dont remember it can someone please help
 

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MHF Helper
Aug 2008
12,883
4,999
1.x+3/2x>1
2.4/x+1<3/1
3.3/x-2≤1

i know theres a method for this to find 2 solutions but i dont remember it can someone please help
What you have written is extremely confusing... Please use brackets where they're needed.

I.e. in Q1 is it \(\displaystyle \frac{x + 3}{2x} > 1\) or \(\displaystyle x + \frac{3}{x} > 1\)?

Is Q2 \(\displaystyle \frac{4}{x + 1} < \frac{3}{1}\) or \(\displaystyle \frac{4}{x} + 1 < \frac{3}{1}\)?

Is Q3 \(\displaystyle \frac{3}{x - 2} \leq 1\) or \(\displaystyle \frac{3}{x} - 2 \leq 1\)?
 
May 2010
39
0
What you have written is extremely confusing... Please use brackets where they're needed.

I.e. in Q1 is it \(\displaystyle \frac{x + 3}{2x} > 1\) or \(\displaystyle x + \frac{3}{x} > 1\)?

Is Q2 \(\displaystyle \frac{4}{x + 1} < \frac{3}{1}\) or \(\displaystyle \frac{4}{x} + 1 < \frac{3}{1}\)?

Is Q3 \(\displaystyle \frac{3}{x - 2} \leq 1\) or \(\displaystyle \frac{3}{x} - 2 \leq 1\)?
or (question 1)


(question 2)


(question 3)

sorry im new to this site im just getting use to it those are the questions
 
May 2010
39
0
What you have written is extremely confusing... Please use brackets where they're needed.

I.e. in Q1 is it \(\displaystyle \frac{x + 3}{2x} > 1\) or \(\displaystyle x + \frac{3}{x} > 1\)?

Is Q2 \(\displaystyle \frac{4}{x + 1} < \frac{3}{1}\) or \(\displaystyle \frac{4}{x} + 1 < \frac{3}{1}\)?

Is Q3 \(\displaystyle \frac{3}{x - 2} \leq 1\) or \(\displaystyle \frac{3}{x} - 2 \leq 1\)?
this is question 1 sorry