S sj9110 Dec 2008 24 0 Jun 19, 2010 #1 I have to find Fy of e^(xe^y) .. Fx is no problem but I can't seem to figure out how to take the partial derivative in terms of y of e^(xe^y) ... the syntax of the two exponential functions is really confusing me. Thanks, Jeff

I have to find Fy of e^(xe^y) .. Fx is no problem but I can't seem to figure out how to take the partial derivative in terms of y of e^(xe^y) ... the syntax of the two exponential functions is really confusing me. Thanks, Jeff

A Ackbeet MHF Hall of Honor Jun 2010 6,318 2,433 CT, USA Jun 19, 2010 #2 There's actually less there than meets the eye. Use the chain rule a few times to get your result.

A adkinsjr Jun 2009 696 170 United States Jun 19, 2010 #3 \(\displaystyle f(x,y)=e^{xe^y}\) To differentiate with respect to y, just remember to use the chain rule. \(\displaystyle \frac{\partial f}{\partial y}=\left(\frac{\partial}{\partial y}xe^y}\right)e^{xe^y} \)

\(\displaystyle f(x,y)=e^{xe^y}\) To differentiate with respect to y, just remember to use the chain rule. \(\displaystyle \frac{\partial f}{\partial y}=\left(\frac{\partial}{\partial y}xe^y}\right)e^{xe^y} \)