Help with calculus question?

Apr 2010
2
0
[FONT=Arial, sans-serif] A curve is defined by the equation[/FONT]
[FONT=Arial, sans-serif]y[/FONT][FONT=Arial, sans-serif]2[/FONT][FONT=Arial, sans-serif] + [/FONT][FONT=Arial, sans-serif]yx [/FONT][FONT=Arial, sans-serif]ln[/FONT][FONT=Arial, sans-serif]x[/FONT][FONT=Arial, sans-serif] = [/FONT][FONT=Arial, sans-serif]x[/FONT][FONT=Arial, sans-serif], [/FONT][FONT=Arial, sans-serif]x[/FONT][FONT=Arial, sans-serif] > 0.[/FONT]


[FONT=Arial, sans-serif]need to show that line x = 1 intersects curve at point A(1,1) and at another point B and find the co-ordinates of B?
[/FONT]
 

skeeter

MHF Helper
Jun 2008
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North Texas
[FONT=Arial, sans-serif] A curve is defined by the equation[/FONT]
[FONT=Arial, sans-serif]y[/FONT][FONT=Arial, sans-serif]2[/FONT][FONT=Arial, sans-serif] + [/FONT][FONT=Arial, sans-serif]yx [/FONT][FONT=Arial, sans-serif]ln[/FONT][FONT=Arial, sans-serif]x[/FONT][FONT=Arial, sans-serif] = [/FONT][FONT=Arial, sans-serif]x[/FONT][FONT=Arial, sans-serif], [/FONT][FONT=Arial, sans-serif]x[/FONT][FONT=Arial, sans-serif] > 0.[/FONT]


[FONT=Arial, sans-serif]need to show that line x = 1 intersects curve at point A(1,1) and at another point B and find the co-ordinates of B?
[/FONT]
\(\displaystyle y^2 + y(1)\ln(1) = 1\)

\(\displaystyle y^2 = 1\)

\(\displaystyle y = \pm 1
\)