Help! Operations of angles?

May 2013
9
0
United States
Perform each of the following operations:
1. 13o48'39" + 18o34'39"
2. 11o23' - 6o50'

Express the following without decimals.
1. 0.1o 2. 15.87​o
 

topsquark

Forum Staff
Jan 2006
11,581
3,455
Wellsville, NY
Perform each of the following operations:
1. 13o48'39" + 18o34'39"
2. 11o23' - 6o50'

Express the following without decimals.
1. 0.1o 2. 15.87​o
What have you been able to do so far?

-Dan
 
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May 2013
9
0
United States
Here's the situation: I'm in an online math class that has absolutely no instruction. The book does not even cover half of the work we have to do. All our instructor gave us to work with is a list of definitions. Therefore, I have no clue what this question is even asking me to do. I managed to guess correctly on the top two answers but I have no idea how to figure out the bottom two. I took geometry five years ago in high school and have not worked with it since. So what have I been able to do so far? Not a thing.
 

Plato

MHF Helper
Aug 2006
22,492
8,653
Here's the situation: I'm in an online math class that has absolutely no instruction. The book does not even cover half of the work we have to do. All our instructor gave us to work with is a list of definitions. Therefore, I have no clue what this question is even asking me to do. I managed to guess correctly on the top two answers but I have no idea how to figure out the bottom two. I took geometry five years ago in high school and have not worked with it since. So what have I been able to do so far? Not a thing.
If we stipulate that above is all absolutely true, then why are you doing in an online course?
If you have to pay for it, then it is a complete waste of money.
Given all that you say, you seem to be in real need of face to face classroom instruction.
 
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May 2013
9
0
United States
I'm in a program that is set up in this way. They have forced us to take two online math courses. Believe me, this is not by my choosing. I've figured it out. Google is a wonderful thing! Thanks anyway!
 

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
Surely you know how to add! That is what the first is asking you to do- together with know that there are 60 seconds in a minute and 60 minutes in a degree.
To add \(\displaystyle 13^o 45' 30''+ 20^0 25' 40''\)
30"+ 40"= 70"= 60"+ 10"= 1' 10"
45'+ 25'= 70' plus that additional minute from the seconds sum is 71'. 71'= 60'+ 11'= \(\displaystyle 1^o 11'
\(\displaystyle 13^o+ 20^o= 33^o\) plus that additional degree from the minutes sum is \(\displaystyle 34^o\).
The sum is \(\displaystyle 34^o 11' 10"\)

To write \(\displaystyle 30.2^o\) "without a decimal", convert that "\(\displaystyle .2^o\)" to minutes and (if necessary) seconds.
Since there are \(\displaystyle 60'\) in a degree, .2 of a degree is (0.2)(60)= 3' so \(\displaystyle 30.2^o= 30^0 3'\).\)