**If 3/5 = x/y, then**

Col A: x - 3

Col B: y – 5

Which col is larger/are they the same/not enough information.

Now, I can solve each and get x-3=(3y/5)-3 and y-5=(5x/3)-5. In this case, the answer is not enough info because it depends on the values of x and y.

But then, You could also do this:

3y=5x. Now by subtracting 15 on both sides

Col A: x - 3

Col B: y – 5

Which col is larger/are they the same/not enough information.

Now, I can solve each and get x-3=(3y/5)-3 and y-5=(5x/3)-5. In this case, the answer is not enough info because it depends on the values of x and y.

But then, You could also do this:

3y-15=5x-15 => 3(y-5)=5(x-3)

=>(y-5)/(x-3)=5/3 so (y-5) is greater than (x-3) so answer is 'B'

Is the second method here the correct way to do this problem?