function point

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
Again, this is all secondary school material. And you still haven't said why you are posting it although you have been asked twice.
 
Jan 2015
30
0
leskovac

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
The problem seems to be that you are using a lot of words whose meanings you do not know!

In particular, while talking about a "new form of function", you do not appear to know what "function" means.
 
  • Like
Reactions: 1 person
Jan 2015
30
0
leskovac
SERBIAN
Pošto sam otkrio nove mogućnosti , moguća rešenja

Na x-koordinati , postoji duž AB , tačka A je nepokretna na x-koordinati , tačka B se nalazi na bilo kojem mestu x-koordinate , opisati ovo funkcijom .

Rešenja : A=a , B=x , AB=y

a) y=|a-x|

b) y=-|a-x|

c) y=a-x

d) y=x-a

GOOGLE TRANSLATOR
Since I discovered new possibilities, possible solutions

On the x-coordinate, there is straight AB, point A is fixed on the x-coordinate, point B is located at any point x-coordinates, to describe this function.

Solutions : A=a , B=x , AB=y

a) y=|a-x|

b) y=-|a-x|

c) y=a-x

d) y=x-a
 
Jan 2015
30
0
leskovac
SERBIAN
Preslikavanje funkcije iz x-koordinate u ravan ( dekartov koordinatni sistem )
y=x-a , x i a ostaju na x-koordinatu , y ide na y-koordinatu .
prati sliku
https://pkxnqg.bn1302.livefilestore.com/y2ms1kFcLvWYclmDavUSyYiiUCkglMB3TYDpjo4I23buEYpvpbcsQS-t8SKGRlC3R5KQkCTJWKmXqZwLRsjG0LNEr5Enn0RwSf8als3QfyMtNqboZSXrNkWxEatBIIWFsQu9UKd0y_reY3YWSh5idkVdC-swrTkqYaXV8fmts9x7Ks/ii.png?psid=1
prave iz x i a paralelne sa y-koordinate
prava iz y paralelna sa x-koordinate
u preseku pravih nastaju tačke A i B
tačke A i B se spajaju i dobija se duž AB
dato je za x=4 , a=2 , y=2
ponovimo postupak za x=3.5 , a=2 , y=1.5 , prati sliku
u preseku pravih nastaju tačke C i D
tačke C i D se spajaju i dobija se duž CD

https://befwwg.bn1302.livefilestore.com/y2mzhIoNBVQOYCOV9gtsE361lcxHSUG2TsUqD3THDqzJpcG02gLWoqZV0m00uCIviOfkBuo8B7buK6gD24pfy8qrLYpGRW-UVWy497HgktTvJFUVd9duY3xBIBwUzvPVl11bpeqEsjSWKTDKraCcJKIy-UHkR4VeCHL_PmPvJTSMeM/i.png?psid=1
spajaju se tačke AC ( BD ) duži AB i CD
tačke ABDC čine površinu za 4≥x≥3.5

GOOGLE TRANSLATOR
The mapping function from the x-coordinates of the plane (Cartesian coordinate system)
y = x-a, x and a remain on the x-coordinate, y goes to the y-coordinate.
view photo
https://pkxnqg.bn1302.livefilestore.com/y2ms1kFcLvWYclmDavUSyYiiUCkglMB3TYDpjo4I23buEYpvpbcsQS-t8SKGRlC3R5KQkCTJWKmXqZwLRsjG0LNEr5Enn0RwSf8als3QfyMtNqboZSXrNkWxEatBIIWFsQu9UKd0y_reY3YWSh5idkVdC-swrTkqYaXV8fmts9x7Ks/ii.png?psid=1
the lines of x and a parallel to the y-coordinates
line of y parallel to the x-coordinate
formed at the intersection of real points A and B
points A and B are combined and gets straight line AB
is given by x = 4, a = 2, y = 2
Repeat for x = 3.5, a = 2, y = 1.5, view photo
formed at the intersection of real points C and D
points C and D are combined and received straight line CD

https://befwwg.bn1302.livefilestore.com/y2mzhIoNBVQOYCOV9gtsE361lcxHSUG2TsUqD3THDqzJpcG02gLWoqZV0m00uCIviOfkBuo8B7buK6gD24pfy8qrLYpGRW-UVWy497HgktTvJFUVd9duY3xBIBwUzvPVl11bpeqEsjSWKTDKraCcJKIy-UHkR4VeCHL_PmPvJTSMeM/i.png?psid=1
connect the dots AC (BD) straight lines AB and CD
ABDC points form the surface of 4≥x≥3.5
 
Jan 2015
30
0
leskovac
How to look graphics functions

a) y=|a-x|
b) y=-|a-x|
c) y=a-x
d) y=x-a
e) y={|a-x|}\(\displaystyle \cup\){-|a-x|}
 

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
How to look graphics functions

a) y=|a-x|
b) y=-|a-x|
c) y=a-x
d) y=x-a
e) y={|a-x|}\(\displaystyle \cup\){-|a-x|}
I am not sure what you mean by this but if you mean "What do the graphs look like?" then
a) y= |a- x|= |x- a| is a straight line with slope -1 for x< a, ending at (a, 0) then a straight line with slope 1 for x> a, starting at x= a. A "V" shape.
b) y= -|a- x|= -|x- a| is a straight line with slope 1 for x< a, ending at (a, 0) then a straight line with slope -1 for x> a, starting at x= a. An upside down "V" shape.
c) y= a- x. A straight line with slope -1 passing through (0, a) and (a, 0).
d) y= x- a. A straight line with slope 1 passing through (0, -a) and (-a, 0).

e) is meaningless- the union is defined for sets, not expressions. If you mean the union of the graphs (which are sets of points) of (a) and (b) then it is two straight lines, with slopes 1 and -1, both passing thorough (a, 0). An "X" shape. It is also the union of the graphs in (c) and (d).

There is nothing new here. This is all pretty standard secondary school math.
 

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
Each of these is wrong.

The red area (extending infinitely) is the graph of the inequality y> |2- x| The graph of y= |2- x| is the boundary of the red area.

The red area is the graph of the inequality y< -|2- x|. The graph of y=-|2- x| is the boundary of the red area.

The graph of y= 2- x is the slanting boundary. The red area shown above the x-axis is the graph of y> 2- x for x< 2. Below the x-axis, it is y< 2- x for x> 2.

The graph of y= x- 2 is the slanting boundary. The red area, for y> 0 is the set of y> x- 2 for x>2. For y< 0, it is the set of y< x- 2 for x< 2.


The graph of that y is the union of the two lines forming boundary. your red are is y> (2-x)(x- 2) (again, NOT "union") for y> 0 and y< (2- x)(x-2) for y< 0.

which are geometric objects obtained for valuesx and y , shape a≥x≥b ( a≥y≥b ) ? , you have a graph
I wonder why you keep posting these when you are paying no attention to the responses.
 
Last edited:
Jan 2015
30
0
leskovac
Each of these is wrong.

The red area (extending infinitely) is the graph of the inequality y> |2- x| The graph of y= |2- x| is the boundary of the red area.
it seems that you are not reading the rules I set , mapped straight line (a and x) not mapped (x) , for your test to see whether or not an innovative mathematician ,
that geometric object in the plane meets these requirements
a ) has six angles
b )the sum of the angles \(\displaystyle 1080^o\)

a)\(\displaystyle y_{x.}=|a_{x.}-x_{x.}|\)
b)\(\displaystyle y_{x.}=-|a_{x.}-x_{x.}|\), the same graph is reversed only to \(\displaystyle 180^o\) , and relates to a negative value y
the scene (\(\displaystyle x.\))x-coordinates , (\(\displaystyle y.\))y-coordinates ,( \(\displaystyle xy.\))plane
Graph functions \(\displaystyle y_{x.}\rightarrow y_{y.}\) , mapped straight line \(\displaystyle (y_{y.},a_{x.},x_{x.})\rightarrow(a_{xy.}x_{xy.})\)
2≥y≥0 ( The general form b≥y≥0 , b>0 ) rectangular isosceles triangle
https://2bl1tq.bn1302.livefilestore.com/y2mRMDHZJSXOSkM9hvlWoCrg7fvVX-EJmwLuyey7VOE-jtJszb4fZIHCC-swg4wshH1UgvCYoFZflpdRxPnAuZW4DY1p_AbLpAQ0I6Jc3AHNbGMIUT93xq118RkPva7zBN1RUVuKqNL12VYCgSDrGVr0A/y1.png?psid=1

3≥y≥1 ( The general form c≥y≥b , b>0 , c>0 ) regular trapeze
https://dc4d8a.bn1302.livefilestore.com/y2mIxEWYLFmp82OKeRb3Jjoq_JjXkXF84ELPR7BLiTow3aT7hCjGAfOzIHpN-mereZQ-bmVfZJUspZMgnaryJfBOZWLZJvOCYUvCsURmxG-MXGuWp0tAufS5C7WL9PS8DTbYrpR0fD2Vhx9lCacxIjf8g/y2.png?psid=1

1≥x≥-1 ( The general form c≥x≥b x<a , c≥x≥b x>a ) rectangular trapeze
https://o9amca.bn1302.livefilestore.com/y2mRNf-wflcI1o1PnWBEvaYhCf1TxO2YuRXQPX3BkQnAM7-fYwzSy0cVcDJB6TNUx_GDsixOGOTsd0pxl6LB9T-5acxgKC9NeiYwlu3A4xbd1C0kGFrYxPxcg6FCWt4FDy7sqTIZNX57SWFbuE4v6HR6w/y3.png?psid=1

6≥x≥-1 ( The general form c≥x≥b , b>a , c<a , |b|\(\displaystyle \neq\)|c|) pentagon
https://pkxoqg.bn1302.livefilestore.com/y2mWMo9jsLjPNe8zc24-VD9lve-TrKvCHhxBx4lN9u7PU2BEH8re9kV5XplLQ21MyBFmiJtJ4rkxDK3F_7S-vGwfJUb5i_ubo0UCZE4gsV6E7FhAJhoyN8Xy_qThLPbQyTNzHDTKaz5o26xnOhTE2PD9Q/y4.png?psid=1
more geometric objects that can be obtained ???