I have a plotted a graph of:

\(\displaystyle \frac{I(t)}{|E_p|^2}=e^{(-2\alpha t^2)}\)

Now I understand that the maximum is when t=0, however what about the full width half max?? Why is the half height 1/e??

Can someone help me obtain the full width half max of this?

Thanks

Chris

\(\displaystyle \frac{I(t)}{|E_p|^2}=e^{(-2\alpha t^2)}\)

Now I understand that the maximum is when t=0, however what about the full width half max?? Why is the half height 1/e??

Can someone help me obtain the full width half max of this?

Thanks

Chris

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