eumyang Jan 2010 278 138 Jul 18, 2010 #2 Geometric series converges if |r| < 1 (where r is the common ratio). Plug in x + 1 for r... \(\displaystyle |x + 1| < 1\) ...and solve for x. Reactions: HallsofIvy

Geometric series converges if |r| < 1 (where r is the common ratio). Plug in x + 1 for r... \(\displaystyle |x + 1| < 1\) ...and solve for x.