F fran1942 Nov 2010 93 0 Jun 7, 2012 #1 Hello, I am trying to find the cartesian equation of the curve in general form. The curve is 'y=1-12t'. I know the final answer is (1-y)^2-24x+48=0 but I only know the first step: i.e. separate to 't= {1-y} / 12' I do not know how to proceed. Can someone show the method for completing this problem. Thanks kindly.

Hello, I am trying to find the cartesian equation of the curve in general form. The curve is 'y=1-12t'. I know the final answer is (1-y)^2-24x+48=0 but I only know the first step: i.e. separate to 't= {1-y} / 12' I do not know how to proceed. Can someone show the method for completing this problem. Thanks kindly.

Sarasij Jun 2011 42 5 India Jun 7, 2012 #2 fran1942 said: Hello, I am trying to find the cartesian equation of the curve in general form. The curve is 'y=1-12t'. I know the final answer is (1-y)^2-24x+48=0 but I only know the first step: i.e. separate to 't= {1-y} / 12' I do not know how to proceed. Can someone show the method for completing this problem. Thanks kindly. Click to expand... You have not specified how 'x' depends on 't'.

fran1942 said: Hello, I am trying to find the cartesian equation of the curve in general form. The curve is 'y=1-12t'. I know the final answer is (1-y)^2-24x+48=0 but I only know the first step: i.e. separate to 't= {1-y} / 12' I do not know how to proceed. Can someone show the method for completing this problem. Thanks kindly. Click to expand... You have not specified how 'x' depends on 't'.