*x*or

*y*. Draw a typical approximating rectangle and label its height and width. (Do this on paper. Your instructor may ask you to turn in this graph.)

This is the solution I got, but it was marked wrong:

x^2-2x = x+4

x^2-2x-x-4 =0

x^2-3x-4 =0

(x+1)(x-4), bounds are (-1,4)

= (int from -1 and 4) x^2-3x-4

=(x^3/3)-(3x^2/(2))-4x

when I plug it in, I get 191/6, but it's wrong, don't know what I did wrong..please help!