Find the indicated intergral

Jun 2010
13
0
\(\displaystyle \int t^{-1/2} (t^2-t+2) dt\)
\(\displaystyle t^{-1/2}= \frac{1}{\sqrt t}\)
I apply the logarithmic rule now?
 

Plato

MHF Helper
Aug 2006
22,508
8,664
\(\displaystyle \int t^{-1/2} (t^2-t+2) dt\)
\(\displaystyle t^{-1/2}= \frac{1}{\sqrt t}\)
I apply the logarithmic rule now?
No indeed.
\(\displaystyle \int t^{-1/2} (t^2-t+2) dt=\int (t^{3/2}-t^{1/2}+2t^{-1/2}) dt\)
 
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Nov 2009
130
24
@Minino777 just learn the basic formulas for solving integrals.
 
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