Find the particular solution(arbitrary constant determined) y'+2xy=5x given that y(0)=1 i got e^-x2 *5e^x2/2+c1

dy/dx + 2y = e^-x

[Note you can only determine the general solution here (arbitrary constant remains unknown)]

i got e^-x(e^x+c) is that final answer right

dy/dx + 2y = e^-x

[Note you can only determine the general solution here (arbitrary constant remains unknown)]

i got e^-x(e^x+c) is that final answer right

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