G George321 Apr 2010 15 0 May 20, 2010 #1 State the coordinates of the verex of the curve \(\displaystyle y=x^2+8x+15\) I have completed the square: \(\displaystyle y=(x+4)^2-1\) I dont understand what the question is asking for or how i can find it though, please explain. Thanks

State the coordinates of the verex of the curve \(\displaystyle y=x^2+8x+15\) I have completed the square: \(\displaystyle y=(x+4)^2-1\) I dont understand what the question is asking for or how i can find it though, please explain. Thanks

masters MHF Helper Jan 2008 2,550 1,187 Big Stone Gap, Virginia May 20, 2010 #2 George321 said: State the coordinates of the verex of the curve \(\displaystyle y=x^2+8x+15\) I have completed the square: \(\displaystyle y=(x+4)^2-1\) I dont understand what the question is asking for or how i can find it though, please explain. Thanks Click to expand... Hi George321, You have just put the general quadratic into vertex form: \(\displaystyle y=a(x-h)^2+k\) in which (h, k) happens to be the vertex.

George321 said: State the coordinates of the verex of the curve \(\displaystyle y=x^2+8x+15\) I have completed the square: \(\displaystyle y=(x+4)^2-1\) I dont understand what the question is asking for or how i can find it though, please explain. Thanks Click to expand... Hi George321, You have just put the general quadratic into vertex form: \(\displaystyle y=a(x-h)^2+k\) in which (h, k) happens to be the vertex.