Hi all, my fractions are not great to be honest but here is my question.

Using addition, solve for a and b:

\(\displaystyle 4a-6b=15\)

\(\displaystyle 6a-4b=10\)

So I find a common multiple of b, I choose to use 24.

\(\displaystyle 16a-24b=60\)

\(\displaystyle 36a-24b=60\)

Now I go ahead and do the addition:

\(\displaystyle 16a-24b=60\)

\(\displaystyle -36a+24b=-60\)

I'm left with: \(\displaystyle -20a=0 == a=0\)

Is this correct so far? If so then I plug the answer back into the equation and get:

\(\displaystyle 4-6b=15\)

I only know from using a website that \(\displaystyle b=-\frac{5}{2}\)

My question is I just don't know how to go about finding the correct fraction, is there a simple method?

Using addition, solve for a and b:

\(\displaystyle 4a-6b=15\)

\(\displaystyle 6a-4b=10\)

So I find a common multiple of b, I choose to use 24.

\(\displaystyle 16a-24b=60\)

\(\displaystyle 36a-24b=60\)

Now I go ahead and do the addition:

\(\displaystyle 16a-24b=60\)

\(\displaystyle -36a+24b=-60\)

I'm left with: \(\displaystyle -20a=0 == a=0\)

Is this correct so far? If so then I plug the answer back into the equation and get:

\(\displaystyle 4-6b=15\)

I only know from using a website that \(\displaystyle b=-\frac{5}{2}\)

My question is I just don't know how to go about finding the correct fraction, is there a simple method?

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