G Glitch Apr 2010 487 9 Jul 7, 2010 #1 Hey guys, I'm having trouble factorising this following: 8x^6 + 64 I've done the following: 8(x^6 + 8) I'm not sure how to factorise this further. Please provide detailed steps so I can understand. Thank you.

Hey guys, I'm having trouble factorising this following: 8x^6 + 64 I've done the following: 8(x^6 + 8) I'm not sure how to factorise this further. Please provide detailed steps so I can understand. Thank you.

Prove It MHF Helper Aug 2008 12,897 5,001 Jul 7, 2010 #2 Use the sum of two cubes rule \(\displaystyle a^3 + b^3 = (a + b)(a^2 - ab + b^2)\). In your case, \(\displaystyle 8(x^6 + 8) = 8[(x^2)^3 + 3^3]\). Reactions: Glitch

Use the sum of two cubes rule \(\displaystyle a^3 + b^3 = (a + b)(a^2 - ab + b^2)\). In your case, \(\displaystyle 8(x^6 + 8) = 8[(x^2)^3 + 3^3]\).

G Glitch Apr 2010 487 9 Jul 7, 2010 #3 Thank you so much! I've been struggling with math, and any help is greatly appreciated!