Group 1 Group 2 Group 3

(61.48, 65.18) ( 60.573, 65.627) ( 62.15, 64.51)

(58.55,65.71) (61.401, 66.479) (60.48, 64.50)

(61.48, 65.18)' ( 61.429, 67.411) ( 60.79, 65.21)

(59.62, 65.614)

(62.24, 64.28)

g)Explain why it does not make sense to count data values that lie in a confidence interval. Think about the random variable that is being used in the problem.

h) Suppose you obtained the heights of ten women and calculated a confidence interval from this information. Without knowing the population mean

*μ*, would you have any way of knowing

**for certain**if your interval actually contained the value of

*μ*? Explain.

Hello I don't understand g but I believed that is impossible because we don't have the information of all the population so we only could hope that our intervals is in 90%. Is that right?