A abdulrehmanshah Nov 2012 96 0 hyderabad May 11, 2013 #1 4 ÷ sin(90º + φ) = 10 ÷ sin(150º – φ) equation 1 tanφ = 4 ÷ √3 equation 2 can anyone tell me how equation 1 is solved to get equation 2

4 ÷ sin(90º + φ) = 10 ÷ sin(150º – φ) equation 1 tanφ = 4 ÷ √3 equation 2 can anyone tell me how equation 1 is solved to get equation 2

G grillage Aug 2012 102 18 Malta May 11, 2013 #2 Start with the identity sin(A+B) = sinAcosB+cosAsinB. See if that helps you to make progress. Reactions: 1 person