e^(i*pi) MHF Hall of Honor Feb 2009 3,053 1,333 West Midlands, England May 22, 2010 #2 tysonrss said: Can someone help me evaluate this? Evaluate (10^-2)^-2 Click to expand... \(\displaystyle (a^b)^c = a^{bc}\) In your case \(\displaystyle 10^{-2 \cdot -2}\) Reactions: tysonrss

tysonrss said: Can someone help me evaluate this? Evaluate (10^-2)^-2 Click to expand... \(\displaystyle (a^b)^c = a^{bc}\) In your case \(\displaystyle 10^{-2 \cdot -2}\)