R rowdy3 Apr 2008 80 2 May 10, 2010 #1 Consider the rational function f(x)= 3x^2 - 12 / x^2 - 3x + 2 A. Give the equation of the horizontal asymptote. B. Give the equation(s) of any vertical asymptotes. Thanks

Consider the rational function f(x)= 3x^2 - 12 / x^2 - 3x + 2 A. Give the equation of the horizontal asymptote. B. Give the equation(s) of any vertical asymptotes. Thanks

R rowdy3 Apr 2008 80 2 May 10, 2010 #2 Is this right? f(x)= (3x^2 - 12) / (x^2 - 3x + 2) horizontal asymptote: y = 3 Vertical Asymptote: (x^2 - 3x + 2) = 0 (x - 2)(x - 1) = 0 x = 2 x = 1 Vertical Asymptotes: x = 1, x = 2

Is this right? f(x)= (3x^2 - 12) / (x^2 - 3x + 2) horizontal asymptote: y = 3 Vertical Asymptote: (x^2 - 3x + 2) = 0 (x - 2)(x - 1) = 0 x = 2 x = 1 Vertical Asymptotes: x = 1, x = 2

tedii Sep 2009 32 4 Milwaukee, Wisconsin May 10, 2010 #3 rowdy3 said: Is this right? f(x)= (3x^2 - 12) / (x^2 - 3x + 2) horizontal asymptote: y = 3 Vertical Asymptote: (x^2 - 3x + 2) = 0 (x - 2)(x - 1) = 0 x = 2 x = 1 Vertical Asymptotes: x = 1, x = 2 Click to expand... Not quite, simplify the numerator too. Something will cancel out and you will have one less vertical asymptote. But you have the general idea behind this.

rowdy3 said: Is this right? f(x)= (3x^2 - 12) / (x^2 - 3x + 2) horizontal asymptote: y = 3 Vertical Asymptote: (x^2 - 3x + 2) = 0 (x - 2)(x - 1) = 0 x = 2 x = 1 Vertical Asymptotes: x = 1, x = 2 Click to expand... Not quite, simplify the numerator too. Something will cancel out and you will have one less vertical asymptote. But you have the general idea behind this.