A Alvy Mar 2010 21 0 May 23, 2010 #1 Hello guys. I know this must be pretty basic. But, I don't get it. How do I solve 0,6 = 0,95^x ? This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated.

Hello guys. I know this must be pretty basic. But, I don't get it. How do I solve 0,6 = 0,95^x ? This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated.

earboth MHF Hall of Honor Jan 2006 5,854 2,553 Germany May 23, 2010 #2 Alvy said: Hello guys. I know this must be pretty basic. But, I don't get it. How do I solve 0,6 = 0,95^x ? This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated. Click to expand... 1. Use logarithms: \(\displaystyle 0,6 = 0,95^x~\implies~x=\log_{0.95}(0.6)\) 2. Now use the base-change-formula: \(\displaystyle x=\log_{0.95}(0.6)~\implies~x=\frac{\ln(0.6)}{\ln(0.95)}\) 3. Hint: Better use a decimal point to separate the integer part from the fraction part of a number. Reactions: Alvy

Alvy said: Hello guys. I know this must be pretty basic. But, I don't get it. How do I solve 0,6 = 0,95^x ? This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated. Click to expand... 1. Use logarithms: \(\displaystyle 0,6 = 0,95^x~\implies~x=\log_{0.95}(0.6)\) 2. Now use the base-change-formula: \(\displaystyle x=\log_{0.95}(0.6)~\implies~x=\frac{\ln(0.6)}{\ln(0.95)}\) 3. Hint: Better use a decimal point to separate the integer part from the fraction part of a number.

e^(i*pi) MHF Hall of Honor Feb 2009 3,053 1,333 West Midlands, England May 23, 2010 #3 Alvy said: Hello guys. I know this must be pretty basic. But, I don't get it. How do I solve 0,6 = 0,95^x ? This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated. Click to expand... \(\displaystyle \ln(0.6) = x\ln(0.95)\) \(\displaystyle x = \frac{\ln(0.6)}{\ln(0.95)}\) Reactions: Alvy

Alvy said: Hello guys. I know this must be pretty basic. But, I don't get it. How do I solve 0,6 = 0,95^x ? This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated. Click to expand... \(\displaystyle \ln(0.6) = x\ln(0.95)\) \(\displaystyle x = \frac{\ln(0.6)}{\ln(0.95)}\)