\(\displaystyle g(x) = \sqrt{3 - x}\)

\(\displaystyle g(x) = (3 - x)^{1/2\)

\(\displaystyle g'(x) = -\dfrac{1}{2}(3 - x)^{-1/2}\)

\(\displaystyle g'(x) = -\dfrac{1}{2}\dfrac{1}{\sqrt{3 - x}}\)

What is the domain of the derivative, in interval notation?

Some hints at problem solving strategy, please.

\(\displaystyle g(x) = (3 - x)^{1/2\)

\(\displaystyle g'(x) = -\dfrac{1}{2}(3 - x)^{-1/2}\)

\(\displaystyle g'(x) = -\dfrac{1}{2}\dfrac{1}{\sqrt{3 - x}}\)

What is the domain of the derivative, in interval notation?

Some hints at problem solving strategy, please.

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