Hello i need help with this differential equations system!

x,u and l are functions of t... so u(t), x(t) and l(t)

tf is free.

Could you find the solutions?

\(\displaystyle

\frac{dx}{dt}=-x+u

\)

\(\displaystyle

\frac{dl}{dt}=l

\)

\(\displaystyle

l -2u-2=0

\)

boundary conditions

x(0)=1

x(tf)=0

l(tf)=2

x,u and l are functions of t... so u(t), x(t) and l(t)

tf is free.

Could you find the solutions?

\(\displaystyle

\frac{dx}{dt}=-x+u

\)

\(\displaystyle

\frac{dl}{dt}=l

\)

\(\displaystyle

l -2u-2=0

\)

boundary conditions

x(0)=1

x(tf)=0

l(tf)=2

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