H henry May 2010 6 0 May 14, 2010 #1 I have been stuck on this question for about an hour now, can you please help Q. the point (4,-3) is on one end of the diameter of a circle centre (6,5). Find the coordinates on the point on the opposite end of that diameter.

I have been stuck on this question for about an hour now, can you please help Q. the point (4,-3) is on one end of the diameter of a circle centre (6,5). Find the coordinates on the point on the opposite end of that diameter.

S sa-ri-ga-ma Jun 2009 806 275 May 14, 2010 #2 henry said: I have been stuck on this question for about an hour now, can you please help Q. the point (4,-3) is on one end of the diameter of a circle centre (6,5). Find the coordinates on the point on the opposite end of that diameter. Click to expand... Center is the mid point of the opposite points of a diameter. If (x, y) are the co-ordinates of the other end of the diameter, then find the mid point of the diameter and equate it to the co-ordinates of the center. Reactions: henry

henry said: I have been stuck on this question for about an hour now, can you please help Q. the point (4,-3) is on one end of the diameter of a circle centre (6,5). Find the coordinates on the point on the opposite end of that diameter. Click to expand... Center is the mid point of the opposite points of a diameter. If (x, y) are the co-ordinates of the other end of the diameter, then find the mid point of the diameter and equate it to the co-ordinates of the center.

11rdc11 Jul 2007 894 298 New Orleans May 14, 2010 #3 henry said: I have been stuck on this question for about an hour now, can you please help Q. the point (4,-3) is on one end of the diameter of a circle centre (6,5). Find the coordinates on the point on the opposite end of that diameter. Click to expand... \(\displaystyle \frac{5-(-3)}{6-2}=\frac{8}{2}\) Now add \(\displaystyle 6+2= 8\) and \(\displaystyle 5 + 8 = 13\) so your other point for the diameter is (8,13) Reactions: henry

henry said: I have been stuck on this question for about an hour now, can you please help Q. the point (4,-3) is on one end of the diameter of a circle centre (6,5). Find the coordinates on the point on the opposite end of that diameter. Click to expand... \(\displaystyle \frac{5-(-3)}{6-2}=\frac{8}{2}\) Now add \(\displaystyle 6+2= 8\) and \(\displaystyle 5 + 8 = 13\) so your other point for the diameter is (8,13)