the function is \(\displaystyle f(x)=xe^2x\)
find equation of tangent line at x=1
this is what I did
\(\displaystyle f'(x)=x*(e^2x)*2 + e^2x\)
\(\displaystyle f'(1)=3*e^2\)
so the equation of tangent line is
\(\displaystyle y=3x*e^2\)
is this correct?
find equation of tangent line at x=1
this is what I did
\(\displaystyle f'(x)=x*(e^2x)*2 + e^2x\)
\(\displaystyle f'(1)=3*e^2\)
so the equation of tangent line is
\(\displaystyle y=3x*e^2\)
is this correct?