Determining cubic equation

Mar 2019
5
0
Canada
Just need assurance if i'm correct or not.

"Find the cubic equation that has zeros at -8, -4, and 13 if f(-10)=138[FONT=LatoWeb, Helvetica Neue, Helvetica, Arial, sans-serif]"[/FONT]

this is what i did but i think i'm not right. Can someone help correct it?

 
Dec 2014
133
103
USA
$f(x) = a(x+8)(x+4)(x-13)$

$f(-10)=138 \implies 138=a(-2)(-6)(-23) \implies a= \dfrac{138}{12(-23)}=-\dfrac{1}{2}$

Therefore, $f(x)=-\dfrac{1}{2}(x+8)(x+4)(x-13)$
 
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Jun 2013
1,112
590
Lebanon
\(\displaystyle f(-10)=138\)

therefore it should be

\(\displaystyle 138=a(x+8)(x+4)(x-13)\) where $x=-10$
 
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